题解 | #字符串通配符#

#include <cctype>
#include <iostream>
#include <regex>
using namespace std;

int main() {
    string wildcard;
    string totest;
    string reg;
    getline(cin,wildcard);
    getline(cin,totest);
    int flag = 0;
    for(auto x:wildcard){
        if(x=='?'){
            reg+="[0-9a-zA-Z.]";
            flag = 0;
            continue;
        }if(x=='*'){
            if(flag == 1){
                continue;
            }else{
                reg+="[0-9a-zA-Z.]*";
                flag = 1;
                continue;
            }

        }else{
            flag = 0;
            x = tolower(x);
            reg.push_back(x);
        }
}
regex r(reg);
if(regex_match(totest, r)){
    cout<<"true";
}else{
    cout<<"false";
}
}
// 64 位输出请用 printf("%lld")

正则表达式很慢