题解 | #称砝码#
称砝码
https://www.nowcoder.com/practice/f9a4c19050fc477e9e27eb75f3bfd49c
#include <iostream>
#include <vector>
using namespace std;
int main() {
int n;
while (cin >> n) { // 注意 while 处理多个 case
vector<int> weight(n);
int sum = 0;
for (int i = 0; i < n; i++)
cin >> weight[i];
for (int i = 0; i < n; i++) {
int nums;
cin >> nums;
sum += nums * weight[i];
while (--nums) {
weight.push_back(weight[i]);
}
}
vector<int> dp(sum + 1, 0);
dp[0] = 1;
for (int i = 0; i < weight.size(); i++) {
// 表示j重量是否可以称到
for (int j = sum; j >= weight[i]; j--) {
if (dp[j]) continue;
dp[j] = dp[j - weight[i]];
}
}
sum = 0;
for (int i : dp)
sum += i;
cout << sum << endl;
}
return 0;
}
// 64 位输出请用 printf("%lld")
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