题解 | #识别有效的IP地址和掩码并进行分类统计#

import sys
import re

pattern = r'^([0-9]{1,3}.){3}([0-9]{1,3}){1}$'
DATA = []
for line in sys.stdin:
    DATA.append(line.strip())  # 使用strip()删除每行末尾的换行符

A, B, C, D, E, F, L = 0, 0, 0, 0, 0, 0, 0

for data in DATA:
    data = data.split('~') 
    ip = re.match(pattern, data[0])
    dom = re.match(pattern, data[1])

    # 判断是否匹配不合法
    if ip is None or dom is None:
        F += 1 
        print(ip, dom)
        continue

    # 判断是否数值不合法
    ip, dom = ip.group(), dom.group()
    ip, dom = ip.split('.'), dom.split('.')
    ip = [int(x) for x in ip]
    dom = [int(x) for x in dom]

    def catch_256 (arr): 
        for i in range(4):
            if arr[i]>255:
                return True
        return False

    if catch_256(ip) or catch_256(dom):
        F+=1
        # print(ip, dom)
        continue

    # 不计数
    if ip[0] == 0 or ip[0] == 127:
        continue

    # 判断掩码是否合法
    dom_x = 0
    for d in dom:
        dom_x = dom_x * 256 + d
    dom_bin = bin(dom_x)
    dom_re = re.match(r'^0b1+0+$', dom_bin)
    if dom_re is None:
        F += 1
        # print(ip, dom)
        continue
    
    # 判断是否是私网
    if ip[0] == 10:
        L += 1
        # continue
    elif ip[0] == 172 and ip[1] >= 16 and ip[1] <= 31:
        L += 1
        # continue
    elif ip[0] == 192 and ip[1] == 168:
        L+= 1
        # continue
    
    if ip[0] > 0 and ip[0] <= 126:
        A += 1
        # print('A:', ip, dom)
        continue
    elif ip[0] >= 128 and ip[0] <= 191: 
        B += 1
        continue
    elif ip[0] >= 192 and ip[0] <= 223:
        C += 1
        continue
    elif ip[0] >= 224 and ip[0] <= 239:
        D += 1
        continue
    elif ip[0] >= 240 and ip[0] <= 255:
        E += 1
        continue

print(A, B, C, D, E, F, L )