题解 | #字符串加密#

#include <iostream>
using namespace std;

int main() {
    string str;

    string strafter;
    string strkey;

    cin >> str;
    cin >> strkey;

    for (auto &it : str)
    {
        if (string::npos == strafter.find(it))
        {
            strafter += it;
        }
    }

    for (char ch = 'a'; ch <= 'z'; ch++)
    {
        if (string::npos == strafter.find(ch))
        {
            strafter += ch;
        }
    }

    string strout;
    for (char ch : strkey)
    {
        int n = ch - 'a';
        strout += strafter[n];
    }

    cout << strout;
    return 0;
}
// 64 位输出请用 printf("%lld")