题解 | #牛牛的线段#
牛牛的线段
https://www.nowcoder.com/practice/f72c56ed71664af082c921bf79861c85
#include <stdio.h>
#include <math.h>
int main()
{
int x1,y1;
scanf("%d %d\n",&x1,&y1);
int x2,y2;
scanf("%d %d\n",&x2,&y2);
int ret=pow((x1-x2),2)+pow((y1-y2),2);
printf("%d",ret);
return 0;
}
