题解 | #输出单向链表中倒数第k个结点#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
    // Write your code here
    const lines = [];
    while ((line = await readline())) {
        lines.push(line);
    }
    for (let j = 0; j < lines.length; j = j + 3) {
        let s1 = lines[j + 1].split(" ").map((v) => Number(v));
        let s2 = lines[j + 1].split(" ").map((v) => Number(v));
        let k = Number(lines[j + 2]);
        let i = 0;
        let cur1 = s1[i];
        let cur2 = s2[k];
        while (cur2) {
            cur1 = s1[i];
            cur2 = s2[k + i];
            i++;
        }

        console.log(cur1);
    }
})();