题解 | #没有重复项数字的全排列#
没有重复项数字的全排列
https://www.nowcoder.com/practice/4bcf3081067a4d028f95acee3ddcd2b1
import java.util.*;
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param num int整型一维数组
* @return int整型ArrayList<ArrayList<>>
*/
public ArrayList<ArrayList<Integer>> permute (int[] num) {
ArrayList<ArrayList<Integer>> list = new ArrayList<ArrayList<Integer>>();
ArrayList<Integer> integers = new ArrayList<>();
boolean[] used = new boolean[num.length];
int[] array = Arrays.stream(num).sorted().toArray();
generateNumbers(array,integers,list,used);
return list;
}
private static void generateNumbers(int[] num, ArrayList<Integer> integers, ArrayList<ArrayList<Integer>> list, boolean[] used) {
if(integers.size()>=num.length){
list.add(new ArrayList<>(integers));
return;
}
for (int i = 0; i < num.length; i++) {
if(used[i]||integers.size()>=num.length){
continue;
}
used[i]=true;
integers.add(num[i]);
generateNumbers(num,integers,list,used);
integers.remove(integers.size()-1);
used[i]=false;
}
}
}
