题解 | #自动售卖机#
自动售卖机
https://www.nowcoder.com/practice/487953e6d3e3434988e0dd6960b6c9f8
`timescale 1ns/1ns
module sale(
input clk ,
input rst_n ,
input sel ,//sel=0,5$dranks,sel=1,10&=$drinks
input [1:0] din ,//din=1,input 5$,din=2,input 10$
output reg [1:0] drinks_out,//drinks_out=1,output 5$ drinks,drinks_out=2,output 10$ drinks
output reg change_out
);
parameter IDLE = 0;
parameter WAIT = 1;
reg [1:0] state;
reg [1:0] nstate;
always @(posedge clk or negedge rst_n) begin
if (!rst_n)
state <= IDLE;
else
state <= nstate;
end
always @(*) begin
if(!rst_n) begin
nstate <= IDLE;
drinks_out <= 0;
change_out <= 0;
end
else begin
case(state)
IDLE: begin
case(sel)
0: begin
nstate <= IDLE;
end
1: begin
case(din)
0: nstate <= IDLE;
1: nstate <= WAIT;
2: nstate <= IDLE;
endcase
end
endcase
end
WAIT: begin
case(din)
0: nstate <= WAIT;
1: nstate <= IDLE;
2: nstate <= IDLE;
endcase
end
endcase
end
end
always @(posedge clk or negedge rst_n) begin
if (!rst_n) begin
drinks_out <= 0;
change_out <= 0;
end
else begin
case (state)
IDLE: begin
case(sel)
0:begin
if (din == 0) begin
drinks_out <= 0;
change_out <= 0;
end
else if (din == 1) begin
drinks_out <= 2'b01;
change_out <= 0;
end
else begin
drinks_out <= 2'b01;
change_out <= 1;
end
end
1:begin
if (din == 0) begin
drinks_out <= 0;
change_out <= 0;
end
else if (din == 1) begin
drinks_out <= 0;
change_out <= 0;
end
else begin
drinks_out <= 2'b10;
change_out <= 0;
end
end
endcase
end
WAIT: begin
case(din)
0:begin
drinks_out <= 0;
change_out <= 0;
end
1:begin
drinks_out <= 2'b10;
change_out <= 0;
end
2:begin
drinks_out <= 2'b10;
change_out <= 1;
end
endcase
end
endcase
end
end
endmodule
该题主要分为IDLE和WAIT两个状态,sel信号优先级高,作为一级状态跳转判断条件。
如能成功完成购买或者根本未投钱则次态还是IDLE,
仅当投入钱且钱不够的时候次态为WAIT。


