题解 | #牛群的能量值#
牛群的能量值
https://www.nowcoder.com/practice/fc49a20f47ac431981ef17aee6bd7d15
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* ListNode(int x) : val(x), next(nullptr) {}
* };
*/
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param l1 ListNode类
* @param l2 ListNode类
* @return ListNode类
*/
ListNode* addEnergyValues(ListNode* l1, ListNode* l2) {
// write code here
int flag = 0;
ListNode* a = l1;
ListNode* b = l2;
ListNode* res = l1;
int alen = 0;
int blen = 0;
while(a != nullptr)
{
alen++;
a =a->next;
}
while(b != nullptr)
{
blen++;
b = b->next;
}
a = l1;
b = l2;
if(alen < blen)
{
swap(a, b);
res = l2;
}
while (a->next != nullptr) {
if(b != nullptr)
{
a->val = a->val + b->val + flag;
if(a->val >= 10)
{
a->val = a->val % 10;
flag = 1;
a = a->next;
b = b->next;
continue;
}
a = a->next;
b = b->next;
flag = 0;
}else {
a->val = a->val + flag;
if(a->val >= 10)
{
a->val = a->val % 10;
flag = 1;
a = a->next;
continue;
}
a = a->next;
flag = 0;
}
}
if(b) a->val = a->val + b->val + flag;
else a->val += flag;
if(a->val >= 10)
{
a->val = a->val % 10;
a->next = new ListNode(1);
}
return res;
}
};