题解 | #自动售卖机#
自动售卖机
https://www.nowcoder.com/practice/487953e6d3e3434988e0dd6960b6c9f8
`timescale 1ns/1ns
module sale(
input clk ,
input rst_n ,
input sel ,//sel=0,5$dranks,sel=1,10&=$drinks
input [1:0] din ,//din=1,input 5$,din=2,input 10$
output reg [1:0] drinks_out,//drinks_out=1,output 5$ drinks,drinks_out=2,output 10$ drinks
output reg change_out
);
//写状态机主要是为了处理:买B饮料但只投了5元的情况
reg [1:0] state ,nxt_state;
parameter idle = 2'b01,
B_DIN1 = 2'b10;
always@(posedge clk or negedge rst_n)
if(!rst_n)
state <= idle;
else
state <= nxt_state;
always@(*)
case(state)
idle:begin
if(sel==1 && din==1)
nxt_state <= B_DIN1;
else
nxt_state <= idle;
end
B_DIN1: begin
if(din==0)
nxt_state <= B_DIN1; //直到这5元钱算清楚再跳出去
else
nxt_state <=idle;
end
default: nxt_state <=idle;
endcase
//drinks_out
always@(posedge clk or negedge rst_n) begin
if(!rst_n)
drinks_out <= 0;
else if(sel==0 && state==idle && din>2'd0)
drinks_out <= 2'd1;
else if((sel==1 && state==idle && din==2'd2)||(sel==1 && state==B_DIN1 && din>2'd0))
//我真是傻了,一直提示这里有编译错误,后来发现是少个括号,写下来提醒自己一下这个愚蠢的小错误
drinks_out <= 2'd2;
else
drinks_out <= 2'd0;
end
//change_out
always@(posedge clk or negedge rst_n) begin
if(!rst_n)
change_out <= 0;
else if((sel==0 && din==2'd2)||(sel==1 && state==B_DIN1 && din==2'd2))
change_out <= 1;
else
change_out <= 0;
end
endmodule


