题解 | #字符金字塔#
字符金字塔
https://ac.nowcoder.com/acm/problem/22209
正反打印两次字母
#include<stdio.h>
int main(){int a,b,c;
char n;
scanf("%c",&n);
a=n-'A';
for (int i=0;i<=a;i++){
for (int j=1;j<=a-i;j++)printf (" ");
for (int j=0;j<i;j++)printf ("%c",'A'+j);
for (int j=i+1;j>0;j--)printf ("%c",'A'+j-1);
printf ("\n");
}
return 0;
}
