题解 | 链表中倒数最后k个结点
链表中倒数最后k个结点
https://www.nowcoder.com/practice/886370fe658f41b498d40fb34ae76ff9
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* ListNode(int x) : val(x), next(nullptr) {}
* };
*/
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param pHead ListNode类
* @param k int整型
* @return ListNode类
*/
ListNode* FindKthToTail(ListNode* pHead, int k) {
// write code here
//空链表检测
int listLength = 0;
if(pHead != nullptr)
listLength++;
else
return nullptr;
//计算链表长度
auto head = pHead;
auto current = head;
while (current->next != nullptr) {
current = head->next;
head = current;
listLength++;
}
//链表长度小于k
if(k > listLength)
return nullptr;
//返回该链表中倒数第k个节点
int index = 0;
head = pHead;
current = head;
while (index++ < listLength-k) {
current = head->next;
head = current;
}
return head;
}
};
#链表中倒数K个结点##链表#