题解 | 字符串变形
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param s string字符串
# @param n int整型
# @return string字符串
#
class Solution:
def trans(self , s: str, n: int) -> str:
# write code here
# 分割单词
words = s.split(' ')
# 反转单词顺序
words = words[::-1]
# 反转每个字符的大小写
for i in range(len(words)):
words[i] = words[i].swapcase()
# 拼接结果
return ' '.join(words)
