题解 | 公共子串计算
公共子串计算
https://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
import sys
s = input()
t = input()
max_common_string_length = 0
if len(s) >= len(t):
for i in range(len(s)):
for j in range(i, len(t)):
if t[i:j+1] in s and len(t[i:j+1]) > max_common_string_length:
max_common_string_length = len(t[i:j+1])
else:
for i in range(len(t)):
for j in range(i, len(s)):
if s[i:j+1] in t and len(s[i:j+1]) > max_common_string_length:
max_common_string_length = len(s[i:j+1])
print(max_common_string_length)

