题解 | 矩阵转置
矩阵转置
https://www.nowcoder.com/practice/351b3d03e410496ab5a407b7ca3fd841
import sys
n, m = map(int, input().split())
arr = list(input().split() for _ in range(n))
newarr = [["0"] *n for _ in range(m)]
for i in range(n):
for j in range(m):
newarr[j][i] = arr[i][j]
for i in newarr:
print(' '.join(i))
# print(*i)
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