题解 | 重复的DNA序列

class Solution:
    def repeatedDNA(self, DNA: str) -> List[str]:
        result = []
        n = len(DNA)
        for i in range(n - 9):  
            substring = DNA[i:i+10]
            if substring in DNA[i+1:] and substring not in result:
                result.append(substring)
        return result