题解 | 时间转换
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <iostream>
using namespace std;
int main() {
int a, b;
cin >> a;
cout << a / 3600 << " " << (a / 60) %60 << " " << a % 60 <<endl;
return 0;
}
// 64 位输出请用 printf("%lld")
