题解 | 单组_spj判断数组之和
单组_spj判断数组之和
https://www.nowcoder.com/practice/da783089da3b4a3188d240e1b7ac4b23
import sys
n, m = map(int, sys.stdin.readline().split())
res = [1]*(n - 1) + [m-(n-1)]
print(" ".join(map(str, res)))
- [1]*(n - 1) 分配 n-1个
- + 连接
单组_spj判断数组之和
https://www.nowcoder.com/practice/da783089da3b4a3188d240e1b7ac4b23
import sys
n, m = map(int, sys.stdin.readline().split())
res = [1]*(n - 1) + [m-(n-1)]
print(" ".join(map(str, res)))
相关推荐