题解 | 异常的邮件概率
异常的邮件概率
https://www.nowcoder.com/practice/d6dd656483b545159d3aa89b4c26004e
select date, round(avg(type = 'no_completed'), 3) as p
from email
where send_id in (
select id from user
where is_blacklist = 0
)
and receive_id in (
select id from user
where is_blacklist = 0
)
group by date
order by date asc
