题解 | 牛牛学数列5
牛牛学数列5
https://www.nowcoder.com/practice/6db6674518a9456198c166bcd0d2aaa1
#include <stdio.h>
int main() {
int n = 0;
scanf("%d",&n);
int arr[47];
arr[0]=1;
arr[1]=1;
if (n == 1 || n == 2) {
printf("1");
return 0;
}
for(int i = 2;i<n;i++){
arr[i]=arr[i-1]+arr[i-2];
}
printf("%d",arr[n-1]);
return 0;
}
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