题解 | B=A×A
B=A×A
https://www.nowcoder.com/practice/21132ecf432b45a5a8187ea074a5d71e
import sys
import math
def main():
input=sys.stdin.read().split()
t=int(input[0])
for i in range(1,t+1):
b=int(input[i])
sqrt_b=int(math.sqrt(b))
while(sqrt_b+1)**2<=b:
sqrt_b+=1
while sqrt_b **2>b:
sqrt_b-=1
print(sqrt_b)
main()
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