题解 | KiKi判断上三角矩阵
KiKi判断上三角矩阵
https://www.nowcoder.com/practice/9a6786c28cdb45f9b991685f867b5d08
n = int(input())
ge = 0
z = 0
for i in range(n):
l = list(map(int, input().split()))
s = ge
if s != 0:
for j in range(s):
t = l[j]
if t != 0:
z = z + 1
ge = ge + 1
if z == 0:
print('YES')
else:
print('NO')
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