题解 | 牛客每个人最近的登录日期(四)
牛客每个人最近的登录日期(四)
https://www.nowcoder.com/practice/e524dc7450234395aa21c75303a42b0a
select date, count(distinct case when datediff(date,first_day)=0 then user_id end) as new from ( select user_id, date, min(date) over(partition by user_id ) as first_day from login ) t group by date;
查看1道真题和解析