题解 | 字符个数统计
字符个数统计
https://www.nowcoder.com/practice/eb94f6a5b2ba49c6ac72d40b5ce95f50
import sys
p = sys.stdin.readline().strip()
Onlynum = set(p)
count = 0
for i in Onlynum:
if 0 <= ord(i) <= 127:
count += 1
print(count)
有点习惯性想多了，一开始还想着建个集合挨个查重，结果后面一想，又不需要顺序，我直接去重不行吗....
