#include <stdio.h>
int main() {
int a, b,c,d,e;
scanf("%d",&a);
for(b=1;b<=a;b++){
scanf("%d %d",&c,&d);
e=c+d;
printf("%d\n",e);
}
} 原来可以边输入边输出。
#include <stdio.h>
int main() {
int T = 0, a = 0, b = 0;
scanf("%d", &T);
while (T--)
{
scanf("%d %d", &a, &b);
printf("%d\n", a + b);
}
return 0;
}
import java.util.*;
public class Main{
public static void main(String[] args){
Scanner in = new Scanner(System.in);
int a = in.nextInt();
for (int i=0;i<a;i++){
int b = in.nextInt();
int c = in.nextInt();
System.out.println(c+b);
}
}
} #include <stdio.h>
int main() {
int n = 0, i = 0;
int arr[1000] = { 0 };
scanf("%d", &n);
for (i = 0; i < n; i++) {
int i1 = 0, i2 = 0;
scanf("\n%d %d", &i1, &i2);
int sum = i1 + i2;
arr[i] = sum;
}
int x = 0;
for (x = 0; x < n; x++) {
printf("%d\n", arr[x]);
}
return 0;
}//我以为是先全部输入再一起出结果 #include <stdio.h>
int main(){
int t,a,b;
scanf("%d",&t);
while(scanf("%d%d",&a,&b)!=EOF){
printf("%d\n",a+b);
}
return 0;
} #include <stdio.h>
int main() {
int t,s,sum=0;
int arr[100][2];
scanf("%d",&t);
for(s=0;s<t;s++){
for (int i=0;i<2;i++) {
scanf("%d",&arr[s][i]);
}
}
for (s=0;s<t;s++) {
for (int i=0;i<2;i++ ) {
sum+=arr[s][i];
}
printf("%d\n",sum);
sum=0;
}
return 0;
}