素数判断__牛客网

Python3

爱健身的牛油果很愤怒

T = int(input())

for _ in range(T):

n = int(input())

if n<2:

print('No')

continue

for i in range(2, int(n**0.5)+1):

if n%i==0:

print('No')

break

else:

print('Yes')

发表于 2025-12-17 22:48:43 回复(0)

Python3

躺平又起来了的小飞象很刻苦

t=int(input())
for i in range(t):
    n=int(input())
    s=0
    for j in range(2,n):
        if n % j ==0:
            s+=1
    if s==0 and n>1:
        print('Yes')
    else:
        print('No')

发表于 2025-11-23 17:22:24 回复(0)

Python3

牛客623830950号

importmath

num = int(input(""))

lst = []

fori in range(1, num + 1):

number = int(input(""))

lst.append(number)

fornumber in lst:

if0<= number <= 1:

print("No")

else:

fori in range(2, int(math.sqrt(number)) + 1):

ifnumber % i == 0:

print("NO")

break

else:

print("YES")我代码错在哪

发表于 2025-11-20 13:32:40 回复(0)

Python3

意若久时天然呆

T=int(input())
p=1<=T<=10
if p:
    for i in range(T):
        p3=0
        n=int(input())
        p1=1<=n<=10**5
        p2=n==1
        if not p1:continue
        for j in range(2,int(n**0.5)+1):
            if j==n:continue
            if n%j==0:
                p3=1
                break
        print('No'if p2+p3 else'Yes')
else:print('请满足1≦T≦10的正整数')

发表于 2025-10-29 11:23:57 回复(0)

Python3

木木E12

import math

def isprime(n):

if n == 1:

return False

for i in range(2, math.isqrt(n)+1, 1):

if n % i == 0:

return False

return True

T = int(input())

for i in range(T):

n = int(input())

if isprime(n):

print('Yes')

else:

print('No')

发表于 2025-08-13 16:18:21 回复(0)

Python3

zyy218

T = int(input())

def prime(x:int):

flag = True

if x < 2:

flag = False

else:

for i in range(2, x):

if x % i == 0:

flag = False

break

return flag

for i in range(1, T+1):

n = int(input())

if prime(n):

print('Yes')

else:

print('No')

发表于 2025-08-04 11:03:05 回复(0)

Python3

友好的牛油在研究求职打法

from math import sqrt
t=int(input()) for i in range(1,t+1):
    n=int(input()) if n==1: print('No') elif n==2: print('Yes') else:
        is_prime = True  for j in range(2,int(sqrt(n)) + 1):
            
            a=n%j if a==0:
                is_prime = False   break  print('Yes' if is_prime else 'No')

发表于 2025-07-25 22:37:11 回复(0)

Python3

极客喵

import math

T : int = int(input())
for j in range(T):
    n : int = int(input())
    isPrime : bool = True
    if n <= 1:
        isPrime = False

    for i in range(2, int(math.sqrt(n)) + 1, 1):
        if n % i == 0:
            isPrime = False

    print("Yes" if isPrime else "No")

发表于 2025-07-24 10:43:33 回复(0)

Python3

勤劳的大魔王只想搞钱

t = int(input())

for i in range(t):

n = int(input())

s = False

if n==1:

print('No')

continue

if n==2:

print('Yes')

continue

for j in range(2,n):

if n%j==0:

s = True

break

print('No') if s else print('Yes')

发表于 2025-07-13 23:08:42 回复(0)

Python3

LI005

import math

T = int(input())

for i in range (T):
n = int(input())
if n == 1:
print("No")
continue
for j in range (2, int(math.sqrt(n)+1)):
if n % j == 0:
print("No")
break
else:
print("Yes")

发表于 2025-07-13 08:04:02 回复(0)

Python3

hovee

# 碰碰运气

import random

[print(['Yes','No'][random.randint(0,1)]) for i in range(int(input()))]

发表于 2025-07-07 22:42:45 回复(0)

素数判断

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