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简单密码

[编程题]简单密码

热度指数：321669 时间限制：C/C++ 1秒，其他语言2秒空间限制：C/C++ 32M，其他语言64M
算法知识视频讲解

$\hspace{15pt}$ 规定这样一种密码的变换方法：
$\hspace{23pt}\bullet\,$ 对于密码中的小写字母，参考九键手机键盘，将它们映射为对应的数字，具体地， $\mathtt{abc}$ 对应数字 $2$ 、 $\mathtt{def}$ 对应数字 $3$ 、 $\mathtt{ghi}$ 对应数字 $4$ 、 $\mathtt{jkl}$ 对应数字 $5$ 、 $\mathtt{mno}$ 对应数字 $6$ 、 $\mathtt{pqrs}$ 对应数字 $7$ 、 $\mathtt{tuv}$ 对应数字 $8$ 、 $\mathtt{wxyz}$ 对应数字 $9$ ；
$\hspace{23pt}\bullet\,$ 对于密码中的大写字母，先将其转换为小写，然后向后移动一位，即 $\mathtt{Z}$ 转换为 $\mathtt{a}$ ， $\mathtt{A}$ 转换为 $\mathtt{b}$ ， $\mathtt{B}$ 转换为 $\mathtt{c}$ ， $\cdots$ ， $\mathtt{Y}$ 转换为 $\mathtt{z}$ ， $\mathtt{Z}$ 转换为 $\mathtt{a}$ 。
$\hspace{23pt}\bullet\,$ 对于密码中的数字，保持不变。

$\hspace{15pt}$ 现在，请你将给定的密码按照上述规则进行变换。

输入描述:

在一行上输入一个长度为  的字符串  ，代表给定的密码。

输出描述:

在一行上输出一个字符串，代表变换后的密码。

示例1

输入

NowCoder123

输出

o69d6337123

算法知识视频讲解

Python

牛思军

res = ""
alph_map = {"a":2, "b":2, "c":2, "d":3, "e":3,  "f":3, "g":4, "h":4, "i":4, "j":5, "k":5, "l":5,
       "m":6, "n":6, "o":6, "p":7, "q":7, "r":7, "s":7, "t":8, "u":8, "v":8, "w":9, "x":9,
             "y":9, "z":9}
for i in input():
    if i.isalpha():
        if 65<=ord(i)<90:
            i = chr(ord(i)+33)
            res += i
        elif i == "Z":
            res += "a"
        else:
            res += str(alph_map[i])
    else:
        res += i
print(res)

发表于 2021-06-05 01:48:12 回复(0)

Python

牛客564856240号

写个很蠢但很好理解的方法：

import sys

dic = {'a':'2','b':'2','c':'2','d':'3','e':'3','f':'3',
'g':'4','h':'4','i':'4','j':'5','k':'5','l':'5',
'm':'6','n':'6','o':'6','p':'7','q':'7','r':'7',
's':'7','t':'8','u':'8','v':'8','w':'9','x':'9',
'y':'9','z':'9','A':'b','B':'c','C':'d','D':'e',
'E':'f','F':'g','G':'h','H':'i','I':'j','J':'k',
'K':'l','L':'m','M':'n','N':'o','O':'p','P':'q',
'Q':'r','R':'s','S':'t','T':'u','U':'v','V':'w',
'W':'x','X':'y','Y':'z','Z':'a','0':'0','1':'1',
'2':'2','3':'3','4':'4','5':'5','6':'6','7':'7',
'8':'8','9':'9'}
code = ''
for s in sys.stdin:
for i in s.strip():
code += dic[i]
print(code)

发表于 2021-05-31 19:04:53 回复(0)

Python

牛客诶谁

import sys

str1 = 'abcdefghijklmnopqrstuvwxyz'
str2 = '22233344455566677778889999'

def func(s):
    res = []
    for c in s:
        # 小写字母
        if c.islower():
            idx = str1.index(c)
            res.append(str2[idx])
        # 大写字母
        elif c.isupper():
            tmp_c = c.lower()
            idx = str1.index(tmp_c)
            # 如果是最后一个字母，则为a
            if  idx == len(str1)-1:
                idx = 0
            else:
                idx += 1
            res.append(str1[idx])
        else:
            res.append(c)
    return ''.join(res)


for line in sys.stdin:
    print(func(line.strip()))

发表于 2021-05-09 22:01:59 回复(0)

Python

牛客73635540号

while True:
    try:
        s = input()
        dict1="ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"
        dict2="bcdefghijklmnopqrstuvwxyza22233344455566677778889999"

        out = ''
        for i in s:
            if i.isalpha():
                index = dict1.find(i)
                out += dict2[index]
            else:
                out += i
        print(out)
    except:
        break

发表于 2021-04-07 16:43:07 回复(0)

Python

牛客541273514号

def szm(str):
    sc=''
    if str<='c':
        sc+='2'
    if str>='d' and str<='f':
        sc+='3'
    if str>='g' and str<='i':
        sc+='4'
    if str>='j' and str<='l':
        sc+='5'
    if str>='m' and str<='o':
        sc+='6'
    if str>='p' and str<='s':
        sc+='7'
    if str>='t' and str<='v':
        sc+='8'
    if str>='w': 
        sc+='9'
    return sc

def dzm(str):
    sc=''
    zm='abcdefghijklmnopqrstuvwxyz'
    new=str.lower()
    addre=zm.find(new)
    if addre != 25:
        sc+=zm[addre+1]
    else:
        sc+='a'
    return sc

def mm(str):
    n=len(str)
    sc=''
    zm='abcdefghijklmnopqrstuvwxyz'
    zmb='ABCDEFGHIJKLMNOPQRSTUVWXYZ'
    for i in range(n):
        if str[i]>='a' and str[i]<='z':
            sc+=szm(str[i])
        if str[i]>='A' and str[i]<='Z':
            sc+=dzm(str[i])
        if str[i] not in zm and str[i] not in zmb:
            sc+=str[i]
    print(sc)

while True:
    try:
        a=input()
        mm(a)
    except:
        break

发表于 2021-04-03 22:35:11 回复(0)

Python

牛客622181604号

letter = 'abcdefghijklmnopqrstuvwxyz'

def Lettolet(Lett):
lett = Lett.lower()
for i in range(len(letter)):
if letter[i] == lett:
return letter[(i + 1) % len(letter)]

def lettonum(let):
if let == 'a' or let == 'b' or let == 'c':
return 2
if let == 'd' or let == 'e' or let == 'f':
return 3
if let == 'g' or let == 'h' or let == 'i':
return 4
if let == 'j' or let == 'k' or let == 'l':
return 5
if let == 'm' or let == 'n' or let == 'o':
return 6
if let == 'p' or let == 'q' or let == 'r' or let == 's':
return 7
if let == 't' or let == 'u' or let == 'v':
return 8
if let == 'w' or let == 'x' or let == 'y' or let == 'z':
return 9

while True:
try:
string = input()
sec = ''
for i in range(len(string)):
if string[i].isdigit():
sec = sec + string[i]
elif string[i] == string[i].upper():
sec = sec + str(Lettolet(string[i]))
else:
sec = sec + str(lettonum(string[i]))
print(sec)
except:
break

发表于 2021-03-27 18:44:22 回复(0)

Python

二年三班的牛客

while True:
    try:
        str = input()
        password = []
        for x in str:
            if x.isupper() == True and x != 'Z':
                password.append(chr(ord(x) + 33))
            elif x == 'Z':
                password.append('a')
            elif x.islower() == True:
                if x in 'abc':
                    password.append('2')
                if x in 'def':
                    password.append('3')
                if x in 'ghi':
                    password.append('4')
                if x in 'jkl':
                    password.append('5')
                if x in 'mno':
                    password.append('6')
                if x in 'pqrs':
                    password.append('7')
                if x in 'tuv':
                    password.append('8')
                if x in 'wxyz':
                    password.append('9')
            else:
                password.append(x)
        print(''.join(password))
    except EOFError:
        break

发表于 2021-03-26 19:00:29 回复(0)

Python

孔亚伟

import re
s2num = {
"abc": "2",
"def": "3",
"ghi": "4",
"jkl": "5",
"mno": "6",
"pqrs": "7",
"tuv": "8",
"wxyz": "9"
}
DS = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
DS2XS = {}
for i in range(len(DS)):
DS2XS[DS[i]] = i + 1

DS2XS["Z"] = 0

real_passwd = ""
while True:
try:
see_passwd = input()
for s in see_passwd:
if re.match(r"[^A-Za-z]", s):
real_passwd += s
elif s in DS2XS:
real_passwd += DS[DS2XS[s]].lower()
else:
for k in s2num:
if s in k:
real_passwd += s2num[k]
break
print(real_passwd)
except:
break

发表于 2021-03-21 16:44:53 回复(0)

Python

爱睡懒觉的帕丁顿

dic={'abc':'2','def':'3','ghi':'4','jkl':'5','mno':'6','pqrs':'7','tuv':'8','wxyz':'9'}
while True:
try:
new = ''
string = input()
for i in string:
ASCII = ord(i)
if ASCII>=65 and ASCII<=90:
new+=chr((ASCII+33-97)%26+97)
elif ASCII>=97and ASCII<=122:
for j in dic.keys():
if i in j:
new+=dic[j]
break
else:
new+=i
print(new)
except:
break

发表于 2021-03-19 10:16:49 回复(0)

Python

牛客568538357号

while True:
try:
s = input()
res =""
dic = {
'1':['1'],
'2':['a','b','c'],
'3':['d','e','f'],
'4':['g','h','i'],
'5':['j','k','l'],
'6':['m','n','o'],
'7':['p','q','r','s'],
'8':['t','u','v'],
'9':['w','x','y','z'],
'0':['0']
}
for i in range(len(s)):
if s[i].isalpha():
if s[i].islower():
for j in dic:
if s[i] in dic[j]:
res+=j
else:
if s[i] == 'Z':
res += 'a'
else:
res+=chr(ord(s[i])+1).lower()
elif s[i].isdigit():
res += s[i]
print(res)
except:
break

发表于 2021-03-12 09:44:27 回复(0)

Python

潘光祥

s=''
while True:
try:
a=input()
for i in range(len(a)):
if a[i].isupper():
if a[i]!='Z': s+=chr(ord(a[i].lower())+1)
if a[i]=='Z': s+='a'
if a[i].islower():
if a[i] in 'abc': s+='2'
if a[i] in 'def': s+='3'
if a[i] in 'ghi': s+='4'
if a[i] in 'jkl': s+='5'
if a[i] in 'mno': s+='6'
if a[i] in 'pqrs': s+='7'
if a[i] in 'tuv': s+='8'
if a[i] in 'wxyz': s+='9'
if a[i].isalpha()== False: s+=a[i]
except:
break
print(s)

发表于 2021-03-01 18:22:36 回复(0)

Python

刷题上头条

import re
lower = re.compile(r'[a-z]')
upper = re.compile(r'[A-Z]')
while True:
    try:
        pw = input()
        if len(pw) >100 : break
        res = list(pw)
        mydict = {"abc":"2","def":"3","ghi":"4","jkl":"5","mno":"6","pqrs":"7","tuv":"8","wxyz":"9"}
        for i in range(len(res)) :
            
            if lower.search(res[i]) :
                for j in mydict.keys():
                    if res[i] in j :
                        res[i] = mydict[j]
            if upper.search(res[i]) :
                if res[i] == "Z" :
                    res[i] = "a"
                    continue
                res[i] = chr(ord(res[i].lower()) + 1)
        print("".join(res))
    except:
        break

发表于 2021-02-20 15:00:22 回复(0)

Python

牛客974564935号

alphabet1 = {
    "a": "2", "b": "2", "c": "2",
    "d": "3", "e": "3", "f": "3",
    "g": "4", "h": "4", "i": "4",
    "j": "5", "k": "5", "l": "5",
    "m": "6", "n": "6", "o": "6",
    "p": "7", "q": "7", "r": "7", "s": "7",
    "t": "8", "u": "8", "v": "8",
    "w": "9", "x": "9", "y": "9", "z": "9",
}
alphabet2 = "_ABCDEFGHIJKLMNOPQRSTUVWXYZ"
x = raw_input()
y = []
for i in range(0, len(x)):
    if x[i].isdigit():
        y.append(x[i])
    if x[i].islower():
        y.append(alphabet1[x[i]])
    if x[i].isupper():
        temp = (alphabet2.index(x[i])+1) % 26
        if temp == 0:
            temp = 26
        y.append(alphabet2[temp].lower())
print "".join(y)

发表于 2021-01-14 00:01:37 回复(0)

Python

Jc77

letter2number = {'abc': '2', 'def': '3', 'ghi': '4', 'jkl': '5', 'mno': '6', 'pqrs': '7', 'tuv': '8', 'wxyz': '9'}
password = input().rstrip()
wordlist = list(password)
lowercase = 0
for j in range(len(wordlist)):
    for i in letter2number:
        if wordlist[j] in i:
            wordlist[j] = letter2number[i]
            lowercase = 1
            break
    if not wordlist[j].isdigit() and not lowercase:
        if wordlist[j] == 'Z':
            wordlist[j] = 'a'
        else:
            wordlist[j] = chr(ord(wordlist[j]) + 33)
    lowercase = 0
print(''.join(wordlist))

编辑于 2020-12-23 10:50:18 回复(0)

Python

大溪地渔民

import sys


a = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"
b = "bcdefghijklmnopqrstuvwxyza222333444555666777788899990123456789"
output = ""

for s in sys.stdin:
    s = s.strip()
    for c in s:
        output += b[a.index(c)]
        
print(output)

发表于 2020-12-14 20:17:21 回复(0)

Python

牛客896589627号

hash_dict = {
'abc': '2',
'def': '3',
'ghi': '4',
'jkl': '5',
'mno': '6',
'pqrs': '7',
'tuv': '8',
'wxyz': '9'
}
while True:
try:
string = list(input())
for i in range(len(string)):
if string[i].islower():
for k in hash_dict:
if string[i] in k:
string[i] = hash_dict[k]

elif string[i].isupper():
if string[i] == 'Z':
string[i] = 'a'
else:
string[i] = (chr(ord(string[i]) + 1)).lower()
print(''.join(string))
except:
break

发表于 2020-11-29 15:17:53 回复(0)

Python

Trr_Krr

import string

a = input()

upper = string.ascii_uppercase
lower = string.ascii_lowercase

sercert_list = [['abc','2'],['def','3'],['ghi','4'],['jkl','5'],['mno','6'],['pqrs','7'],['tuv','8'],['wxyz','9']]

new_passwd = ''

for i in a:
    if i in upper:
        if i == 'Z':
            new_i = 'a'
            new_passwd = new_passwd + new_i
        else:
            upper_index = upper.index(i)
            new_i = lower[upper_index+1]
            new_passwd = new_passwd + new_i
    elif i in lower:
        for j in sercert_list:
            if i in j[0]:
                new_i = j[1]
                new_passwd = new_passwd + new_i

    else:
        new_passwd = new_passwd + i

print(new_passwd)

发表于 2020-11-25 23:04:48 回复(0)

Python

乐观的lishan

# 2020年11月16日21:25:08
while True:
    try:
        clear = input()
        password = ""
        for i in range(len(clear)):
            if "A"<=clear[i]<"Z":
                password += chr(ord(clear[i].lower())+1)
            elif clear[i] == "Z":
                password += "a"
            elif clear[i] in "abc":
                password += "2"
            elif clear[i] in "def":
                password += "3"
            elif clear[i] in "ghi":
                password += "4"
            elif clear[i] in "jkl":
                password += "5"
            elif clear[i] in "mno":
                password += "6"
            elif clear[i] in "pqrs":
                password += "7"
            elif clear[i] in "tuv":
                password += "8"
            elif clear[i] in "wxyz":
                password += "9"
            else:
                password += clear[i]
        print(password)
    except:
        break

编辑于 2020-11-16 21:53:11 回复(0)