C. Tic-tac-toe

链接:https://codeforces.com/problemset/problem/3/C

Certainly, everyone is familiar with tic-tac-toe game. The rules are very simple indeed. Two players take turns marking the cells in a 3 × 3grid (one player always draws crosses, the other — noughts). The player who succeeds first in placing three of his marks in a horizontal, vertical or diagonal line wins, and the game is finished. The player who draws crosses goes first. If the grid is filled, but neither Xs, nor 0s form the required line, a draw is announced.

You are given a 3 × 3 grid, each grid cell is empty, or occupied by a cross or a nought. You have to find the player (first or second), whose turn is next, or print one of the verdicts below:

  • illegal — if the given board layout can't appear during a valid game;
  • the first player won — if in the given board layout the first player has just won;
  • the second player won — if in the given board layout the second player has just won;
  • draw — if the given board layout has just let to a draw.

Input

The input consists of three lines, each of the lines contains characters ".", "X" or "0" (a period, a capital letter X, or a digit zero).

Output

Print one of the six verdicts: first, second, illegal, the first player won, the second player won&nbs***bsp;draw.

Examples

input

Copy

X0X
.0.
.X.

output

Copy

second

代码:

#include<bits/stdc++.h>
using namespace std;
long long n,t,a,b,c,l,j,r,k,d,ans,max1=0,mod=1e9+7;
char x[10][10];
long long m1,m2;
int main()
{
	m1=0;
	m2=0;
	for(int i=1;i<=3;i++)
	{
		for(int j=1;j<=3;j++)
		{
			cin>>x[i][j];
			if(x[i][j]=='0')
			m1++;
			else if(x[i][j]=='X')
			m2++;
		}
	}
	k=0;
	if(m1>m2||m2-m1>1)
	cout<<"illegal";
	else
	{
		if(x[1][1]==x[1][2]&&x[1][1]==x[1][3]||(x[1][1]==x[2][2]&&x[1][1]==x[3][3])||(x[1][1]==x[2][1]&&x[1][1]==x[3][1]))
		{
			if(x[1][1]=='X'&&k==0)
			k=1;
			else if(x[1][1]=='X'&&k==2)
			{
				cout<<"illegal";
				return 0;
			}
			else if(x[1][1]=='0'&&k==0)
			{
				k=2;
			}
			else if(x[1][1]=='0'&&k==1)
			{
				cout<<"illegal";
				return 0;
			}
		}
		if(x[2][1]==x[2][2]&&x[2][2]==x[2][3])
		{
			if(x[2][1]=='X'&&k==0)
			k=1;
			else if(x[2][1]=='X'&&k==2)
			{
				cout<<"illegal";
				return 0;
			}
			else if(x[2][1]=='0'&&k==0)
			{
				k=2;
			}
			else if(x[2][1]=='0'&&k==1)
			{
				cout<<"illegal";
				return 0;
			}
		}
		if(x[3][1]==x[3][2]&&x[3][2]==x[3][3]||(x[3][1]==x[2][2]&&x[2][2]==x[1][3]))
		{
			if(x[3][1]=='X'&&k==0)
			k=1;
			else if(x[3][1]=='X'&&k==2)
			{
				cout<<"illegal";
				return 0;
			}
			else if(x[3][1]=='0'&&k==0)
			{
				k=2;
			}
			else if(x[3][1]=='0'&&k==1)
			{
				cout<<"illegal";
				return 0;
			}
		}
		if(x[1][2]==x[2][2]&&x[2][2]==x[3][2])
		{
			if(x[1][2]=='X'&&k==0)
			k=1;
			else if(x[1][2]=='X'&&k==2)
			{
				cout<<"illegal";
				return 0;
			}
			else if(x[1][2]=='0'&&k==0)
			{
				k=2;
			}
			else if(x[1][2]=='0'&&k==1)
			{
				cout<<"illegal";
				return 0;
			}
		}
		if(x[1][3]==x[2][3]&&x[2][3]==x[3][3])
		{
			if(x[1][3]=='X'&&k==0)
			k=1;
			else if(x[1][3]=='X'&&k==2)
			{
				cout<<"illegal";
				return 0;
			}
			else if(x[1][3]=='0'&&k==0)
			{
				k=2;
			}
			else if(x[1][3]=='0'&&k==1)
			{
				cout<<"illegal";
				return 0;
			}
		}
		if(k==1&&m1==m2-1)
		cout<<"the first player won";
		else if(k==1)
		cout<<"illegal";
		else if(k==2&&m1==m2)
		{
			cout<<"the second player won";
		}
		else if(k==2)
		{
			cout<<"illegal";
		}
		else
		{
			if(m1+m2==9)
			cout<<"draw";
			else
			{
				if(m1<m2)
				cout<<"second";
				else
				cout<<"first";
			}
		}
	}
} 

 

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11-28 13:56
已编辑
吉林建筑大学
所有好工作吻上来:最近可能压力比较大吧,面试的时候已经不屑于去说一些违心的话了,今天这场面试我真是没控制住啊,感觉我已经要发火了
实习学到最有价值的工作习...
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