题解 | #字符串变形#
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param s string字符串
# @param n int整型
# @return string字符串
#
class Solution:
def trans(self , s: str, n: int) -> str:
# write code here
all= s.split(' ')
all = all[::-1]
result = ''
for item in all:
item= item.swapcase()
result = result + item+' '
print(result)
return result[:-1]
item.swapcase()这函数很重要
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