题解 | #奇偶统计#
奇偶统计
https://www.nowcoder.com/practice/04de8eb0ecab426fa6be3ae99af17210
#include <stdio.h>
int main() {
int n = 0;
scanf("%d", &n);
int count = 0;
for (int i = 1; i <= n; i++) {
if (i % 2 == 0) {
count++;
}
}
printf("%d %d",n-count,count);
return 0;
}
