题解 | #简单密码#

#include <iostream>
using namespace std;

int main() {
    string a_z = "22233344455566677778889999";
    string password;
    while (cin >> password) {
        for (size_t i = 0; i < password.length(); ++i) {
            char c = password[i];
            if ('a' <= c && c <= 'z') {
                password[i] = a_z[c - 'a'];
            } else if ('A' <= c && c <= 'Z') {
                if (c < 'Z') {
                    password[i] = c + 1 + 32;
                } else {
                    password[i] = 'a';
                }
            }
        }
        cout << password << endl;
    }
}
// 64 位输出请用 printf("%lld")