题解 | #删除有序链表中重复的元素-II#
删除有序链表中重复的元素-II
https://www.nowcoder.com/practice/71cef9f8b5564579bf7ed93fbe0b2024
/*
* function ListNode(x){
* this.val = x;
* this.next = null;
* }
*/
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @return ListNode类
*/
function deleteDuplicates( head ) {
// write code here
let arr = []
let repeatArr = []
let p1 = head
while(p1) {
if (arr.indexOf(p1.val) === -1) {
arr.unshift(p1.val)
}
else {
repeatArr.unshift(p1.val)
}
p1 = p1.next
}
let p2 = new ListNode(1001)
let top = p2
p2.next = head
let left = p2
while(p2) {
if (repeatArr.indexOf(p2.val) !== -1) {
left.next = p2.next
}
else {
left = p2
}
p2 = p2.next
}
return top.next
}
module.exports = {
deleteDuplicates : deleteDuplicates
};

