题解 | #序列检测器(Moore型)#
序列检测器(Moore型)
https://www.nowcoder.com/practice/d5c5b853b892402ea80d27879b8fbfd6
`timescale 1ns/1ns
module det_moore(
input clk ,
input rst_n ,
input din ,
output reg Y
);
// Mealy型:输出信号不仅取决于当前状态,还取决于输入;
// Moore型:输出信号只取决于当前状态;
reg [2:0]crt_state,nxt_state;
parameter s0=0,s1=1,s2=2,s3=3,s4=4;
//三段式
always@(posedge clk or negedge rst_n)
if(!rst_n)
crt_state <= s0;
else
crt_state <= nxt_state;
//这个组合逻辑块会在任何参与运算的信号(crt_state、din、rst_n等)发生变化时就重新计算nxt_state的值,以保证其能实时反映状态的转换条件。
//第二段always块通常是纯组合逻辑,用于根据当前状态以及输入信号等去计算下一个状态nxt_state,所以用always@(*)来对相关信号敏感保证实时响应输入变化进行计算。
always@(*)
if(!rst_n)
nxt_state <= s0;
else begin
case(crt_state)
s0:begin
if(din) nxt_state <= s1;
else nxt_state <= s0;
end
s1:begin
if(din) nxt_state <= s2;
else nxt_state <= s0;
end
s2:begin
if(~din) nxt_state <= s3;
else nxt_state <= s2;
end
s3:begin
if(din) nxt_state <= s4;
else nxt_state <= s0;
end
s4:begin
if(din) nxt_state <= s1;
else nxt_state <= s0;
end
default: nxt_state <= s0;
endcase
end
always@(posedge clk or negedge rst_n)
if(!rst_n)
Y <= 0;
else if(crt_state==s4)
Y <= 1;
else
Y <= 0;
endmodule
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