题解 | 计算日期到天数转换

#include <stdio.h>

int main() 
{
    int year=0;
    int month=0;
    int day=0;
    int sum=0;
    scanf("%d %d %d",  &year, &month, &day);
     int arr[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
     //             1  2  3  4  5  6  7  8  9  10 11 12month
     int resault=0;
     for(int i=1;i<month;i++)   
     {
        if(year%4==0&&year%100!=0 || year%400==0)
        {
            if(i==2)
            {
                arr[i]=29;
            }
            sum = sum +arr[i];
        }
        else
        {
            sum = sum +arr[i];
        }
     }
     resault=sum+day;
     printf("%d",resault);
    return 0;
}