题解 | 汽水瓶

汽水瓶

https://www.nowcoder.com/practice/fe298c55694f4ed39e256170ff2c205f

#include <stdio.h>

int main() {

    int num[10] = {0};
    int count = 0;
    int left = 0;

    for (int i = 0; i < 10; i++) {
        scanf("%d", &num[i]);
    }

    for (int i = 0; i < 10; i++) {
        if ( num[i] <= 0 || num[i]  > 100)
        {
            break;
        }
        if (num[i]  == 1) {
            printf("%d\n", count);
            break;
        } else if ( num[i]  == 2) {
            count = 1;
            printf("%d\n", count);
            break;
        } else {
            count = 0;
            while (num[i]  > 1) {
                count += num[i]  / 3;
                left = num[i] / 3 + num[i]  % 3;
                num[i]  = left;
                if ( num[i]  == 2) {
                    count += 1;
                    break;
                }
            }
            printf("%d\n", count);
        }
    }
    return 0;
}

全部评论

相关推荐

评论
点赞
收藏
分享

创作者周榜

更多
牛客网
牛客网在线编程
牛客网题解
牛客企业服务