题解 | 两个链表的第一个公共结点
两个链表的第一个公共结点
https://www.nowcoder.com/practice/6ab1d9a29e88450685099d45c9e31e46
/*
struct ListNode {
int val;
struct ListNode *next;
ListNode(int x) :
val(x), next(NULL) {
}
};*/
class Solution {
public:
ListNode* FindFirstCommonNode( ListNode* pHead1, ListNode* pHead2) {
ListNode* vh1 = pHead1;
ListNode* vh2 = pHead2;
int l1 = 0;
int l2 = 0;
while(vh1){
l1++;
vh1=vh1->next;
}
while(vh2){
l2++;
vh2=vh2->next;
}
vh1 = pHead1;
vh2 = pHead2;
if(l1 > l2){
for(int i = 0 ; i < l1- l2;i ++){
vh1 = vh1->next;
}
}
else{
for(int i = 0 ; i < l2 - l1 ; i ++){
vh2 = vh2->next;
}
}
while(vh2!=vh1){
vh2 = vh2->next;
vh1 = vh1->next;
}
return vh1;
}
};
OPPO公司福利 1202人发布