题解 | 矩阵转置

/*#include<stdio.h>
int main()
{
	int arr[10][10], n,m;
	printf("输入：");
	scanf("%d %d", &n,&m);
	for (int i = 0; i < n; i++)
	{
		for (int j=0;j<m;j++)
		{
			scanf("%d", &arr[i][j]);
		}
	}
	//遍历一下
	for (int i = 0; i < n; i++)
	{
		for (int j = 0; j < m; j++)
		{
			printf("%d", arr[i][j]);
			printf(" ");
		}
		printf("\n");
	}
	//转置矩阵
	for (int i = 0; i < m; i++)
	{
		for (int j = 0; j < n; j++)
		{
			printf("%d", arr[j][i]);
			printf(" ");
		}
		printf("\n");
	}
	/*for (int j = 0; j < m; j++)
	{
		for (int i = 0; i < n; i++)
		{
			printf("%d", arr[i][j]);
			printf(" ");
		}
		printf("\n");
	}
	
	return 0;
}*/
#include <stdio.h>

int main()
{
    int n = 0;
    int m = 0;
    int arr[10][10] = { 0 };
    scanf("%d %d", &n, &m);
    int i = 0;
    int j = 0;
    for (i = 0; i < n; i++)
    {
        for (j = 0; j < m; j++)
        {
            scanf("%d", &arr[i][j]);
        }
    }
    for (i = 0; i < m; i++)
    {
        for (j = 0; j < n; j++)
        {
            printf("%d ", arr[j][i]);
        }
        printf("\n");
    }

    return 0;
}