题解 | 序列重组矩阵
序列重组矩阵
https://www.nowcoder.com/practice/7548f8f5e44c42fa84fb2323d899a966
n, m = map(int, input().split())
l = list(map(int, input().split()))
for i in range(n):
l1 = l[0:m]
l = l[m:]
print(' '.join(map(str, l1)))
2025-12-19 15:29 University of Hohenheim Python 发布于浙江
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