题解 | 特殊的科学计数法
特殊的科学计数法
https://www.nowcoder.com/practice/ca0962879d3b40d8bb598fb9a905ac7a
n = input()
c = len(n) - 1
x = int(n[1])
j = 0
if int(n[2]) >= 5:
x = x + 1
if x == 10:
x = 0
j = 1
z = int(n[0]) + j
if z == 10:
print(f'1.0*10^{c+1}')
else:
print(f'{z}.{x}*10^{c}')
