-- 求解用户注册时间 with q0 as ( select uid, date_format(in_time,'%Y-%m-%d') in_time, date_format(out_time,'%Y-%m-%d') out_time, min(date_format(in_time,'%Y-%m-%d')) OVER(PARTITION BY uid ORDER BY date_format(in_time,'%Y-%m-%d')) as min_day, min(date_format(date_add(in_time,interval 1 day),'%Y-%m-%d')) OVER...