题解 | #螺旋矩阵#简洁清爽

class Solution:
    def spiralOrder(self , matrix ):
        res = []
        i, j, di, dj = 0, 0, 0, 1
        n, m = len(matrix), len(matrix[0])
        if matrix != []:
            for _ in range(n * m):
                res.append(matrix[i][j])
                matrix[i][j] = 0
                if matrix[(i+di)%n][(j+dj)%m] == 0:
                    di, dj = dj, -di
                i += di
                j += dj
        return res