题解 | #密码强度等级#

var = input()
## 统计数字、大写字母、小写字母、特殊符号存在的次数
def getCountlist(pwd):
    countNum = 0
    countCharLow = 0
    countCharUpper = 0
    counFh = 0
    fh = "!\"#$%&'()*+,-./:;<=>?@[\\]^_`{|}~"
    for i in range(0, len(pwd)):
        tmp = pwd[i:i+1]
        if tmp.isdecimal():
            countNum = countNum + 1
        if tmp.islower():
            countCharLow = countCharLow + 1
        if tmp.isupper():
            countCharUpper = countCharUpper + 1
        if tmp in fh:
            counFh = counFh + 1
        i = i + 1
    return countNum, countCharLow, countCharUpper, counFh
res = 0
countNum, countCharLow, countCharUpper, counFh = getCountlist(var)
len_var = len(var)
## 判断长度
if len_var <= 4:
    res = res + 5
if len_var >= 5 and len_var <= 7:
    res = res + 10
if len_var >= 8:
    res = res + 25
## 判断数字个数
if countNum == 1:
    res = res + 10
if countNum > 1:
    res = res + 20
## 判断字母
if (countCharLow >= 1 and countCharUpper == 0) or (
    countCharLow == 0 and countCharUpper >= 1
):
    res = res + 10
if countCharLow >= 1 and countCharUpper >= 1:
    res = res + 20
## 判断特殊符号
if counFh == 1:
    res = res + 10
if counFh > 1:
    res = res + 25
## 判断奖励
if countNum >= 1 and countCharLow >= 1 and countCharUpper >= 1 and counFh >= 1:
    res = res + 5
elif countNum >= 1 and countCharLow + countCharUpper >= 1 and counFh >= 1:
    res = res + 3
elif countNum >= 1 and countCharLow + countCharUpper >= 1:
    res = res + 2
## 打印处理
if res >=90:
    print('VERY_SECURE')
if res >=80 and res <90:
    print('SECURE')
if res >=70 and res <80:
    print('VERY_STRONG')
if res >=60 and res <70:
    print('STRONG')
if res >=50 and res <60:
    print('AVERAGE')
if res >=25 and res <50:
    print('WEAK')
elif res >=0 and res < 25 :
    print('VERY_WEAK')