题解 | #牛牛的水杯#
牛牛的水杯
https://www.nowcoder.com/practice/c196c47c23394bf3bdd4f82a838df6bf
#include <stdio.h>
int main() {
int a, b;
scanf("%d%d",&a,&b);
float c;
c = 3.14*(0.1*a)*(0.1*b)*(0.1*b); //一杯的容量
float d = 10.0 / c; //需要的杯子数
if( (d - (int)d) != 0 )
{
d= (int)d + 1;
printf("%d",(int)d);
}else{
printf("%d",(int)d);
}
return 0;
}
